Question Detail

PHY 102 Last Minute Prep Objective Question

Question

A 20-μF capacitor is charged to 200 V. Its stored energy is:
Options
A 4000J
B 4J
C 0.4J
Correct Answer
D 2000J
Correct Answer

Option C is the correct answer.

Detailed Explanation

E = ½CV² = ½ × 20×10⁻⁶ × (200)² = 0.4J

Hint

Don't forget to square the voltage in the energy formula.

Question Info