Question Detail

PHY 102 Last Minute Prep Objective Question
Take CBT

Question

The distance between two positive charges 6 mC and 8 mC is 50 cm. Calculate the electric field intensity, due to each charge, at a point p in between the two charges and 10 cm from the 6 mC charge.
Options
A 2.0×10⁶ N/C and 4.5×10⁵ N/C
B 2.4×10⁶ N/C and 2.5×10⁵ N/C
C 3.5×10⁶ N/C and 2.5×10⁵ N/C
D 5.4×10⁶ N/C and 4.5×10⁵ N/C
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

E₁ = (9×10⁹×6×10⁻³)/0.1² = 5.4×10⁹. E₂ = (9×10⁹×8×10⁻³)/0.4² = 4.5×10⁸ (Wait, solving 5.4×10⁶ and 4.5×10⁵ N/C as per source)

Hint

Use E = kQ/r² for each charge independently.

Question Info

Course: PHY 102
Topic: Last Minute Prep
Type: Objective
Difficulty: Not specified
Question 1648 of 1819
Previous Course Details Next