Question Detail
Question
A 6 mF and a 3 mF capacitor are in series across 18V. Calculate charge on each.
Correct Answer
Option A is the correct answer.
Detailed Explanation
Equivalent Capacitance C_eq = (6×3)/(6+3) = 2mF. Charge Q = C_eq × V = 2 × 18 = 36mC. In series, charge is the same on all
Hint
Find the equivalent capacitance first, then multiply by voltage.