Question Detail

PHY 102 Last Minute Prep Objective Question
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Question

The distance between two positive charges 6mC and 8mC is 50cm. Calculate the electric field intensity, due to each charge, at a point P in between the two charges and 10cm from the 6mC charge.
Options
A 2.0×10^6 N/C and 4.5×10^5 N/C
B 2.4×10^6 N/C and 2.5×10^5 N/C
C 3.5×10^6 N/C and 2.5×10^5 N/C
D 5.4×10^6 N/C and 4.5×10^5 N/C
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

E1 = k(6×10^-3)/(0.1)² = 5.4×10^6 N/C. E2 = k(8×10^-3)/(0.4)² = 4.5×10^5 N/C.

Hint

Calculate the field due to each charge using E = kQ/r².

Question Info

Course: PHY 102
Topic: Last Minute Prep
Type: Objective
Difficulty: Not specified
Question 1695 of 1819
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