Question Detail
Question
A series R-L-C circuit has R = 100Ω, L = 0.5H, C = 10μF connected to a 50Hz source ν = 120 sin ωt. Find the instantaneous current at t = 0.10s
Correct Answer
Option B is the correct answer.
Detailed Explanation
X_L = 2πfL = 157Ω; X_C = 1/(2πfC) = 318Ω; Z = √(100² + (157-318)²) = 189.5Ω; I_peak = 120/189.5 = 0.633A.
Hint
Calculate impedance Z = √(R² + (X_L - X_C)²), then I_peak = V_peak/Z.