Question Detail
Question
The potential of a charge in two dimensions is V(x,y) = 3x + 4y. Determine the electric field intensity in V/m.
Correct Answer
Option D is the correct answer.
Detailed Explanation
E = -∇V = -(3i + 4j). Magnitude = √(3²+4²) = 5. The negative sign indicates direction.
Hint
Electric field is the negative gradient of potential.