Question Detail
Question
A parallel plate capacitor has area 2000cm², plates 1cm apart. Original V₀ = 3000V, drops to 1000V when dielectric inserted. Compute the induced charge Q_ind on each face of the dielectric.
Correct Answer
Option D is the correct answer.
Detailed Explanation
C₀ = ε₀A/d = 1.77×10^-10F; Q₀ = C₀V₀ = 5.31×10^-7C; K = V₀/V = 3; Q_ind = Q₀(1-1/K) = 5.31×10^-7 × 2/3 = 3.54×10^-7 C = 35.4×10^-8 C.
Hint
Induced charge Q_ind = Q₀(1 - 1/K).