Question Detail
Question
An electric motor connected to 240V draws 15A. Armature resistance 0.15Ω. Calculate power developed.
Correct Answer
Option B is the correct answer.
Detailed Explanation
P_input = VI = 240×15 = 3600W. P_loss = I²R = 225×0.15 = 33.75W. P_output = 3600 - 33.75 = 3566.25W.
Hint
Power developed = Input power - Power loss in armature.