Question Detail
Question
A uniform electric field of 4.50kN/C passes through a rectangular surface of area 12cm by 14cm. The field makes an angle of 60° with the normal. Determine the electric flux through the surface.
Correct Answer
Option B is the correct answer.
Detailed Explanation
A = 0.12×0.14 = 0.0168m². Φ = EAcosθ = 4500 × 0.0168 × cos60° = 37.8 Nm²/C.
Hint
Electric flux Φ = EAcosθ.