Question Detail
Question
An atom changing from an energy state of -0.54 eV to an energy state of -0.85 eV will emit a photon whose energy is
Correct Answer
Option A is the correct answer.
Detailed Explanation
When an atom transitions from a higher energy state to a lower energy state, it emits a photon. The energy of the emitted photon is equal to the absolute difference between the initial and final energy states.Initial energy state (Ei) = -0.54 eVFinal energy state (Ef) = -0.85 eVEnergy of the emitted photon (Ephoton) = Ei - EfEphoton = (-0.54 eV) - (-0.85 eV)Ephoton = -0.54 eV + 0.85 eVEphoton = 0.31 eV.
Hint
The energy of an emitted photon corresponds to the energy difference between the initial and final energy levels of the electron, Ephoton = Ehigher - Elower.