Question Detail
Question
An atom changing from an energy state of -0.54 eV to an energy state of -0.85 eV will emit a photon whose energy is:
Correct Answer
Option A is the correct answer.
Detailed Explanation
When an atom transitions from a higher energy state to a lower energy state, it emits a photon with energy equal to the difference between the two energy levels.Initial energy state (E_initial) = -0.54 eVFinal energy state (E_final) = -0.85 eVSince E_initial > E_final, the atom emits a photon.Energy of the photon (E_photon) = E_initial - E_finalE_photon = (-0.54 eV) - (-0.85 eV)E_photon = -0.54 eV + 0.85 eVE_photon = 0.31 eV.
Hint
Photon energy is the absolute difference between the initial and final energy states during an atomic transition.