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PHY 104 PHY 104 Past Questions Objective Question
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Question

The angular velocities of three bodies in simple harmonic motion are ω_1, ω_2, ω_3 with their respective amplitudes as A_1, A_2, A_3. If all the three bodies have the same mass and maximum velocity, then
Options
A A_1ω_1 = A_2ω_2 = A_3ω_3
Correct Answer
B A_1ω_1^2 = A_2ω_2^2 = A_3ω_3^2
C A_1/ω_1 = A_2/ω_2 = A_3/ω_3
D A_1ω_1 = A_2ω_2 = A_3ω_3
Correct Answer

Option A is the correct answer.

Detailed Explanation

In simple harmonic motion (SHM), the maximum velocity (V_max) of an oscillating body is given by the product of its amplitude (A) and angular velocity (ω):V_max = Aω.The problem states that all three bodies have the same maximum velocity. Therefore, their respective products of amplitude and angular velocity must be equal:A_1ω_1 = A_2ω_2 = A_3ω_3.(Note: Option D is identical to A, indicating a likely typo in the original question's options. Assuming A is the intended correct unique option.)

Hint

Recall the formula for maximum velocity in simple harmonic motion (SHM).

Question Info

Course: PHY 104
Topic: PHY 104 Past Questions
Type: Objective
Difficulty: Not specified
Question 693 of 947
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