Question Detail
Question
An atom changing from an energy state of -0.54 eV to an energy state of -0.85 eV will emit a photon whose energy is
Correct Answer
Option A is the correct answer.
Detailed Explanation
When an electron in an atom transitions from a higher energy state to a lower energy state, it emits a photon with energy equal to the difference between the two energy levels.Given:Initial energy state (E_initial) = -0.54 eVFinal energy state (E_final) = -0.85 eVSince E_initial > E_final (as -0.54 > -0.85), energy is emitted.Energy of the emitted photon (E_photon) = E_initial - E_finalE_photon = (-0.54 eV) - (-0.85 eV)E_photon = -0.54 eV + 0.85 eVE_photon = 0.31 eV
Hint
Energy is emitted when an electron transitions from a higher energy level to a lower energy level. The energy of the photon is the absolute difference between these two energy levels.