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PHY 104 PHY 104 Past Questions Objective Question
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Question

The angular velocities of three bodies in simple harmonic motion are ω1, ω2, ω3, with their respective amplitudes as A1, A2, A3. If all three bodies have the same mass and maximum velocity, then:
Options
A ω<sub>1</sub>A<sub>1</sub> = ω<sub>2</sub>A<sub>2</sub> = ω<sub>3</sub>A<sub>3</sub>
Correct Answer
B ω<sub>1</sub><sup>2</sup>A<sub>1</sub> = ω<sub>2</sub><sup>2</sup>A<sub>2</sub> = ω<sub>3</sub><sup>2</sup>A<sub>3</sub>
C ω<sub>1</sub><sup>2</sup>A<sub>1</sub><sup>2</sup> = ω<sub>2</sub><sup>2</sup>A<sub>2</sup><sup>2</sup> = ω<sub>3</sub><sup>2</sup>A<sub>3</sup><sup>2</sup>
D ω<sub>1</sub>A<sub>1</sub><sup>2</sup> = ω<sub>2</sub>A<sub>2</sub><sup>2</sup> = ω<sub>3</sub>A<sub>3</sub><sup>2</sup>
Correct Answer

Option A is the correct answer.

Detailed Explanation

For a body undergoing simple harmonic motion (SHM), the maximum velocity (Vmax) is given by the product of its amplitude (A) and angular velocity (ω): Vmax = Aω.If all three bodies have the same maximum velocity, then A1ω1 = A2ω2 = A3ω3. Therefore, the product of amplitude and angular velocity is constant for all three bodies.

Hint

Recall the formula for maximum velocity in simple harmonic motion.

Question Info

Course: PHY 104
Topic: PHY 104 Past Questions
Type: Objective
Difficulty: Not specified
Question 705 of 947
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