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PHY 104 PHY 104 Past Questions Objective Question

Question

A ray of light travels through transparent plastic to air. The diagram shows the ray entering the air travelling parallel to the surface of the plastic. The refractive index of the plastic is 1.25. What is angle θ, which is the angle of incidence in the plastic?
Options
A 37°
B 39°
C 51°
D 53°
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

This scenario describes a ray of light undergoing refraction at the interface between plastic and air. The ray in air travels parallel to the surface, which means the angle of refraction (r) in the air is 90° (this is the critical angle for the plastic-air interface).According to Snell's Law: n1 sin θ1 = n2 sin θ2Here, n1 = refractive index of plastic = 1.25θ1 = angle θ (angle of incidence in plastic)n2 = refractive index of air ≈ 1θ2 = angle of refraction in air = 90°So, 1.25 * sin θ = 1 * sin 90°1.25 * sin θ = 1 * 1sin θ = 1 / 1.25 = 0.8θ = sin-1(0.8) ≈ 53.13°The closest option is 53°.

Hint

Apply Snell's Law. If the refracted ray travels parallel to the surface, what is the angle of refraction?

Question Info