Question Detail

According to the photoelectric effect, the maximum kinetic energy (KE_max) of ejected electrons is given by KE_max = hf - φ, where h is Planck's constant, f is the frequency of incident radiation, and φ is the work function.First, calculate the energy of the incident photon: E = hf = (6.625 x 10^-34 J.s) * (3.0 x 10^15 Hz) = 1.9875 x 10^-18 J.Convert the work function to Joules: φ = 2.3 eV * (1.602 x 10^-19 J/eV) = 3.6846 x 10^-19 J.Now, calculate KE_max in Joules: KE_max = (1.9875 x 10^-18 J) - (3.6846 x 10^-19 J) = (19.875 - 3.6846) x 10^-19 J = 16.1904 x 10^-19 J.Finally, convert KE_max to electron-volts: KE_max = (16.1904 x 10^-19 J) / (1.602 x 10^-19 J/eV) ≈ 10.106 eV. The closest option is 10.13 eV.