Question Detail
Question
An atom changing from an energy state of -0.54 eV to an energy state of -0.85 eV will emit a photon whose energy is
Correct Answer
Option A is the correct answer.
Detailed Explanation
When an atom transitions from a higher energy state to a lower energy state, it emits a photon with energy equal to the absolute difference between the two energy levels. In this case, the atom goes from -0.54 eV to -0.85 eV. This means it goes from a higher energy state (-0.54 eV is greater than -0.85 eV) to a lower energy state. The energy of the emitted photon is E_photon = E_final - E_initial = -0.85 eV - (-0.54 eV) = -0.31 eV. The magnitude of the emitted energy is 0.31 eV.
Hint
The energy of the emitted photon is the absolute difference between the initial and final energy states.