Question Detail

PHY 104 PHY 104 Past Questions Objective Question

Question

Two points on a travelling wave having frequency 500 Hz and velocity 300 m/s are 60° out of phase, then the minimum distance between the two points is
Options
A 0.2 m
B 0.1 m
Correct Answer
C 0.5 m
D 0.4 m
Correct Answer

Option B is the correct answer.

Detailed Explanation

First, find the wavelength: λ = v/f = 300/500 = 0.6 m. A phase difference of 360° corresponds to one wavelength (λ). A phase difference of 60° corresponds to a path difference (Δx) given by Δx = (Δφ/360°) × λ = (60/360) × 0.6 = 0.1 m.

Hint

Find the wavelength first (λ = v/f). Then use the relationship between phase difference and path difference: Δφ/360° = Δx/λ.

Question Info