Question Detail
Question
A 50 g mass vibrates in SHM at the end of a spring. The amplitude of the motion is 12 cm and the period is 0.1 minutes. What is the maximum speed of the mass.
Correct Answer
Option A is the correct answer.
Detailed Explanation
The maximum speed in SHM is v_max = ωA. The period T = 0.1 minutes = 6 seconds. Angular frequency ω = 2π/T = 2π/6 = π/3 rad/s. Amplitude A = 12 cm = 0.12 m. v_max = (π/3) * 0.12 = 0.1256 m/s. Option C.
Hint
Use v_max = ωA = (2π/T)A.