Question Detail
Question
The work function of a particular metal is 2.00 eV. If the metal is illuminated with monochromatic light of wavelength 550 nm, what is the required stopping potential?
Correct Answer
Option A is the correct answer.
Detailed Explanation
Photon energy E = hc/λ = 1240 eV·nm / 550 nm = 2.2545 eV. Work function φ = 2.00 eV. K_max = E - φ = 0.2545 eV. Stopping potential V₀ = K_max / e = 0.2545 V ≈ 0.26 V.
Hint
Use the photoelectric equation: eV₀ = hf - φ = hc/λ - φ.