Question Detail
Question
Light of constant intensity strikes a metal surface. The frequency of the light is increased from 6.0 × 10^14 cycles per second to 9.0 × 10^14 cycles per second. Photoelectrons are emitted by the metal surface when the frequency reaches 8.0 × 10^14 cycles per second. As the frequency of the incident light increases, the photons striking the metal surface increase in
Correct Answer
Option B is the correct answer.
Detailed Explanation
The energy of a photon is given by E = hf. As frequency increases, the energy of each photon increases. The speed of photons is always c in vacuum. Intensity is related to the number of photons, not their energy per se.
Hint
Photon energy is directly proportional to frequency: E = hf.