Question Detail
Question
The maximum velocity and maximum acceleration of a particle executing S.H.M. are 1 m/s and 3.14 m/s² respectively. The frequency of oscillation for this particle is
Correct Answer
Option A is the correct answer.
Detailed Explanation
For SHM: v_max = ωA and a_max = ω²A. Therefore, a_max/v_max = ω = 3.14/1 = 3.14 rad/s. Frequency f = ω/(2π) = 3.14/(2π) = 0.5 Hz = 0.5 s⁻¹.
Hint
Use the relationships v_max = ωA and a_max = ω²A to find ω.