Question Detail
Question
Photons with energies of 3.9 × 10⁻¹⁹ J strike a photoemissive surface whose work function is 2.9 × 10⁻¹⁹ J. The maximum kinetic energy of the ejected photoelectrons is
Correct Answer
Option A is the correct answer.
Detailed Explanation
The maximum kinetic energy is K_max = E_photon - φ = 3.9e-19 - 2.9e-19 = 1.0 × 10⁻¹⁹ J.
Hint
Use K_max = hf - φ.