Question Detail

PHY 104 PHY 104 Past Questions Objective Question
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Question

The threshold frequency for a photoemissive surface is 4.0 × 10^14 Hz. What is the work function of this surface?
Options
A 1.2 × 10⁻¹⁹ J
B 2.6 × 10⁻¹⁹ J
Correct Answer
C 6.0 × 10¹⁴ J
D 6.1 × 10¹⁷ J
Correct Answer

Option B is the correct answer.

Detailed Explanation

Work function φ = hf₀ = (6.626 × 10^-34)(4.0 × 10^14) = 2.65 × 10^-19 J ≈ 2.6 × 10^-19 J.

Hint

Use φ = hf₀.

Question Info

Course: PHY 104
Topic: PHY 104 Past Questions
Type: Objective
Difficulty: Not specified
Question 838 of 947
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