Question Detail
Question
What is the cut off frequency of the radiation that could eject photoelectrons from sodium which has a work function of 2.3 eV?
Correct Answer
Option D is the correct answer.
Detailed Explanation
f₀ = φ/h = (2.3 × 1.602e-19) / (6.626e-34) = 3.6846e-19 / 6.626e-34 = 5.56 × 10^14 Hz.
Hint
Use f₀ = φ/h.