Question Detail

PHY 104 PHY 104 Past Questions Objective Question
Take CBT

Question

Photons with a frequency of 1.0 × 10²⁰ Hz strike a metal surface. If electrons with a maximum kinetic energy of 3.0 × 10⁻¹⁴ J are emitted, the work function of the metal is
Options
A 1.0 × 10⁻¹⁴ J
B 2.2 × 10⁻¹⁴ J
C 3.6 × 10⁻¹⁴ J
Correct Answer
D 6.6 × 10⁻¹⁴ J
Correct Answer

Option C is the correct answer.

Detailed Explanation

E_photon = hf = (6.626 × 10⁻³⁴)(1.0 × 10²⁰) = 6.626 × 10⁻¹⁴ J. φ = E_photon - K_max = 6.626e-14 - 3.0e-14 = 3.626e-14 J ≈ 3.6e-14 J.

Hint

Use φ = hf - K_max.

Question Info

Course: PHY 104
Topic: PHY 104 Past Questions
Type: Objective
Difficulty: Not specified
Question 893 of 947
Previous Course Details Next