Question Detail
Question
If a particle in SHM has a period of 0.2 s and an amplitude of 9 cm. What is the maximum velocity?
Correct Answer
Option A is the correct answer.
Detailed Explanation
v_max = ωA = (2π/T)A = (2π/0.2) × 9 = 10π × 9 = 90π cm/s.
Hint
v_max = ωA = (2π/T)A.