Question Detail
Question
If the wavelength of a beam of radiated X-ray is 0.62 Å, what is the value of the applied potential difference across the X-ray tube? (1 Å = 10⁻¹⁰ m).
Correct Answer
Option A is the correct answer.
Detailed Explanation
eV = hc/λ. λ = 0.62 Å = 0.62 × 10⁻¹⁰ m. V = hc/(eλ) = (6.626e-34 × 3e8) / (1.602e-19 × 0.62e-10) = 1.9878e-25 / 9.9324e-30 = 20013 V ≈ 20 kV.
Hint
Use eV = hc/λ.