Question Detail
Question
A string has mass 2.5 g and length 0.75 m under tension force of 50 N. Calculate the frequency of the first two harmonics.
Correct Answer
Option A is the correct answer.
Detailed Explanation
μ = m/L = 0.0025 / 0.75 = 0.003333 kg/m. f₁ = (1/2L)√(T/μ) = (1/(1.5))√(50/0.003333) = 0.6667 × √15000 = 0.6667 × 122.47 = 81.65 Hz ≈ 82 Hz. f₂ = 2f₁ = 164 Hz.
Hint
Use f₁ = (1/2L)√(T/μ).