Question Detail
Question
In an experiment using Young's slits, the distance between the center of the interference pattern and the tenth bright fringe on either side is 3.44 cm and the distance between the slits and screen is 2.00 m. If the wavelength of the light used is 5.89 × 10⁻⁷ m, determine the slit separation.
Correct Answer
Option D is the correct answer.
Detailed Explanation
y = mλL/d. m = 10, y = 3.44 cm = 0.0344 m, L = 2.00 m. d = mλL/y = (10 × 5.89e-7 × 2.00) / 0.0344 = 1.178e-5 / 0.0344 = 3.424e-4 m = 0.3424 mm ≈ 0.31 mm.
Hint
Use y = mλL/d.