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MTH 102 MTH 102 Past Questions Objective Question

Question

Find dy/dx, if y = loge cos x
Options
A <i>cotx</i>
B <i>-cotx</i>
C <i>-tanx</i>
Correct Answer
D <i>tanx</i>
Correct Answer

Option C is the correct answer.

Detailed Explanation

The function is y = loge cos x, which is equivalent to y = ln(cos x).To find the derivative, we use the chain rule for natural logarithms: d/dx [ln(f(x))] = f'(x) / f(x).Here, f(x) = cos x.The derivative of f(x) is f'(x) = d/dx (cos x) = -sin x.Substitute these into the chain rule formula:dy/dx = (-sin x) / (cos x).Recall that sin x / cos x = tan x.So, dy/dx = -tan x. This matches option C.

Hint

Remember the chain rule for natural logarithms: d/dx [ln(f(x))] = f'(x) / f(x). Also, recall the derivative of cos x and the definition of tan x.

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