Question Detail

MTH 102 MTH 102 Past Questions Objective Question

Question

Evaluate ∫ cos3x dx
Options
A <i>sin x - (1/3)sin<sup>3</sup>x + C</i>
Correct Answer
B <i>cos x + (1/3)cos<sup>3</sup>x + C</i>
C <i>sec x - (1/3)sec<sup>3</sup>x + C</i>
D <i>tan x - (1/3)tan<sup>3</sup>x + C</i>
Correct Answer

Option A is the correct answer.

Detailed Explanation

To evaluate ∫ cos3x dx, we use the trigonometric identity cos2x = 1 - sin2x.∫ cos3x dx = ∫ cos2x ∙ cos x dx= ∫ (1 - sin2x) ∙ cos x dx.Now, use u-substitution. Let u = sin x.Then, du = cos x dx.Substitute u and du into the integral:= ∫ (1 - u2) du.Integrate term by term:= u - (u3/3) + C.Substitute back u = sin x:= sin x - (sin3x)/3 + C. This matches option A.

Hint

Rewrite cos3x as cos2x ∙ cos x and then use the identity cos2x = 1 - sin2x. After that, use u-substitution with u = sin x.

Question Info