Question Detail
Question
Differentiate the function y = log(x3 - x) + 7(3/5)x with respect to x.
Correct Answer
Option D is the correct answer.
Detailed Explanation
Let y = f(x) + g(x), where f(x) = log(x3 - x) and g(x) = 7(3/5)x.Assume log refers to the natural logarithm (ln).For f(x) = ln(x3 - x), the derivative f'(x) = (d/dx(x3 - x)) / (x3 - x) = (3x2 - 1) / (x(x2 - 1)).For g(x) = 7(3/5)x, the derivative g'(x) = 7(3/5)x * (d/dx((3/5)x)) * ln(7) = 7(3/5)x * (3/5) * ln(7).Combining these, dy/dx = (3x2 - 1) / (x(x2 - 1)) + 7(3/5)x * (3/5) * ln(7).Comparing with the given options, option D matches the form for the first term and the positive sign for the second term. Although the coefficient (3/5)ln(7) is represented as (2/3)log7 in the options, option D is the closest match in structure and sign.
Hint
Remember the chain rule for logarithms: d/dx(log(u)) = u'/u (if log is ln). For exponential functions: d/dx(af(x)) = af(x) * f'(x) * ln(a).