Question Detail
Question
Find dy/dx if y = loge(cosx).
Correct Answer
Option C is the correct answer.
Detailed Explanation
The derivative of y = loge(cosx) (which is ln(cosx)) is found using the chain rule.If y = ln(u), then dy/dx = (1/u) * du/dx.Here, u = cosx.The derivative of u with respect to x is du/dx = -sinx.So, dy/dx = (1/cosx) * (-sinx) = -sinx/cosx = -tanx.This matches option C.
Hint
Recall the derivative of ln(u) and the chain rule for trigonometric functions.