Question Detail
Question
Evaluate lim(x→5) (2x²-9x-5)/(x²-x-20)
Correct Answer
Option B is the correct answer.
Detailed Explanation
Both top and bottom vanish at x=5, so factor: 2x²-9x-5=(2x+1)(x-5) and x²-x-20=(x-5)(x+4). Cancel (x-5), leaving (2x+1)/(x+4), which at x=5 gives 11/9.
Hint
Factor numerator and denominator to cancel the (x-5) term causing the 0/0 form.