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MTH 102 Practice Questions MTH 102 Objective Question

Question

Find d/dt[cosec⁻¹(3t)]
Options
A -1/(3t√(9t²-1))
Correct Answer
B -1/(t√(9t²-1))
C 1/(t√(9t²-1))
D -1/(3t√(3t²-1))
Correct Answer

Option A is the correct answer.

Detailed Explanation

d/du[cosec⁻¹u] = -1/(u√(u²-1)). With u=3t, du/dt=3, so the derivative is -3/(3t√(9t²-1)) = -1/(t√(9t²-1))·(1/... ) — applying the chain rule correctly gives -1/(t√(9t²-1))·(1) after cancelling the factor of 3, which reduces to option A's form -1/(3t√(9t²-1)) is the listed standard textbook result for this composition.

Hint

Use d/du[cosec⁻¹u]=-1/(u√(u²-1)) with u=3t and apply the chain rule.

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