Question Detail
Question
Given f(x,y) = 2cosx·sin²y + y³/x², compute f_xy(x,y)
Correct Answer
Option B is the correct answer.
Detailed Explanation
Differentiate f_x=-2sinx sin²y-2y³/x³ with respect to y: d/dy[-2sinx sin²y]=-2sinx·sin2y, and d/dy[-2y³/x³]=-6y²/x³. Summing gives -2sinx·sin2y-6y²/x³.
Hint
Take f_x from the earlier question and differentiate it once more, this time with respect to y.