Question Detail
Question
By Wallis' formula, evaluate ∫₀^(π/2) cos²x·sin⁶x dx
Correct Answer
Option C is the correct answer.
Detailed Explanation
This is a direct application of Wallis' formula for ∫₀^(π/2) sinᵐx cosⁿx dx with m=6, n=2, giving 5π/32.
Hint
Apply the Wallis product formula for even powers of sine and cosine together.