Question Detail

MTH 102 Practice Questions MTH 102 Objective Question

Question

Find dy/dx of y=cosh³(2x)
Options
A 3cosh²2x sinh2x
B 6cosh²2x sinh2x
Correct Answer
C 3cosh2x sinh2x
D 6sinh²2x sinh2x
Correct Answer

Option B is the correct answer.

Detailed Explanation

By the chain rule: d/dx[cosh³2x] = 3cosh²2x · sinh2x · 2 = 6cosh²2x sinh2x.

Hint

Apply the chain rule for a cube, then again for the inner cosh(2x).

Question Info