Question Detail

MTH 102 Practice Questions MTH 102 Objective Question

Question

∫eˣ/(1-eˣ) dx
Options
A -ln|1-eˣ|
Correct Answer
B ln|1-eˣ|
C x-ln|1-eˣ|
D x-eˣ
Correct Answer

Option A is the correct answer.

Detailed Explanation

Let u=1-eˣ, du=-eˣdx. The integral becomes -∫du/u = -ln|u| = -ln|1-eˣ|.

Hint

Substitute u=1-eˣ so that du matches the numerator up to a sign.

Question Info