Question Detail
Question
If ∫sin³x dx = Acos³x+Bcosx+c, then A-B = ?
Correct Answer
Option B is the correct answer.
Detailed Explanation
∫sin³x dx = -cosx + (1/3)cos³x + c, so A=1/3, B=-1. Then A-B = 1/3-(-1) = 4/3.
Hint
Split sin³x = sinx(1-cos²x), integrate directly, and identify A and B by matching terms.