Question Detail

MTH 102 Practice Questions MTH 102 Objective Question

Question

∫sin²x dx
Options
A ½x - sin2x/4
Correct Answer
B ½x - sin2x/2
C ½x - sin2x/(4x)
D ½x - sin2x/(2x)
Correct Answer

Option A is the correct answer.

Detailed Explanation

Using sin²x = (1-cos2x)/2: ∫sin²x dx = x/2 - sin(2x)/4 + C.

Hint

Use the half-angle identity sin²x=(1-cos2x)/2 before integrating.

Question Info