Question Detail

MTH 102 Practice Questions MTH 102 Objective Question
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Question

Given f(x,y)=3tanx·log_ey - y²e^(3x), compute f_x(x,y)
Options
A 3tanx/y - 2ye^(3x)
B 6log_ey sec²x tanx-9y²e^(3x)
C 3sec²x log_ey-3y²e^(3x)
Correct Answer
D -3tanx/y² - 2e^(3x)
Correct Answer

Option C is the correct answer.

Detailed Explanation

Holding y constant: d/dx[3tanx·lny]=3sec²x·lny, and d/dx[-y²e^(3x)]=-3y²e^(3x). Summing gives 3sec²x·lny-3y²e^(3x).

Hint

Hold y fixed and differentiate each term with respect to x.

Question Info

Course: MTH 102
Topic: Practice Questions MTH 102
Type: Objective
Difficulty: Not specified
Question 907 of 930
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