Question Detail

MTH 102 Practice Questions MTH 102 Objective Question
Take CBT

Question

Find dy/dx of y=cosec(3x/2+1/2)
Options
A -cosec(3x/2+1/2)cot(3x/2+1/2)
B -cosec²(3x/2+1/2)
C (3/2)sec(3x/2+1/2)tan(3x/2+1/2)
D -(3/2)cosec(3x/2+1/2)cot(3x/2+1/2)
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

d/dx[cosec u]=-cosecu·cotu·u'. With u=3x/2+1/2, u'=3/2, so the result is -(3/2)cosec(3x/2+1/2)cot(3x/2+1/2).

Hint

Apply the chain rule for cosecant with the inner linear function 3x/2+1/2.

Question Info

Course: MTH 102
Topic: Practice Questions MTH 102
Type: Objective
Difficulty: Not specified
Question 913 of 930
Previous Course Details Next