Question Detail

MTH 102 Practice Questions MTH 102 Objective Question
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Question

d/dx[3x²sin⁻¹x] equals
Options
A 3xsin⁻¹x+3x²/√(1-x²)
B 3x²sin⁻¹x+6x/√(1-x²)
C 6x/√(1-x²)
D 6xsin⁻¹x+3x²/√(1-x²)
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

By the product rule: d/dx[3x²]·sin⁻¹x + 3x²·d/dx[sin⁻¹x] = 6x·sin⁻¹x + 3x²/√(1-x²).

Hint

Apply the product rule with u=3x² and v=sin⁻¹x.

Question Info

Course: MTH 102
Topic: Practice Questions MTH 102
Type: Objective
Difficulty: Not specified
Question 918 of 930
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