Question Detail
Question
According to the Bohr model, what is the energy of a photon emitted when an electron transitions from n = 4 to n = 2 in a hydrogen atom? (Rydberg constant R_H = 2.18 x 10^-18 J)
Correct Answer
Option B is the correct answer.
Detailed Explanation
Energy delta E = R_H * (1/2^2 - 1/4^2) = 2.18 x 10^-18 * (3/16) = 4.09 x 10^-19 J.
Hint
No hint available