Question Detail
Question
Calculate the work associated with the expansion of a gas from 46 L to 64 L against a constant external pressure of 15 atm (1 atm = 101,325 Pa).
Correct Answer
Option A is the correct answer.
Detailed Explanation
w = -PΔV = -(15 * 101325 Pa) * ((64 - 46) * 10^-3 m³) = -27357.75 J ≈ -27,358 J.
Hint
No hint available