Question Detail
Question
In a trihybrid cross (AaBbCc × AaBbCc) assuming independent assortment and complete dominance, what proportion of the progeny will show the fully dominant phenotype for all three genes?
Correct Answer
Option B is the correct answer.
Detailed Explanation
For each independent locus, the probability of showing the dominant phenotype is 3/4. For three independent genes: (3/4) * (3/4) * (3/4) = 27/64.
Hint
No hint available