Question Detail
Question
Find the value of k such that 2k + 1, 3k + 3, and 5k - 1 are consecutive terms of an arithmetic progression.
Correct Answer
Option A is the correct answer.
Detailed Explanation
Applying 2(3k + 3) = (2k + 1) + (5k - 1) yields 6k + 6 = 7k, which simplifies to k = 6.
Hint
No hint available