Question Detail
Question
A person weighing 75.0 kg running at 1.78 m/s has a kinetic energy of __________ J.
Correct Answer
Option A is the correct answer.
Detailed Explanation
KE = 1/2 * m * v^2 = 0.5 * 75.0 kg * (1.78 m/s)^2 ≈ 119 J.
Hint
Plug the numbers into the kinetic energy formula.